9-4x=3x^2-8x+4

Solution for 9-4x=3x^2-8x+4 equation:

9-4x=3x^2-8x+4

We move all terms to the left:

9-4x-(3x^2-8x+4)=0

We get rid of parentheses

-3x^2-4x+8x-4+9=0

We add all the numbers together, and all the variables

-3x^2+4x+5=0

a = -3; b = 4; c = +5;
Δ = b2-4ac
Δ = 42-4·(-3)·5
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{19}}{2*-3}=\frac{-4-2\sqrt{19}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{19}}{2*-3}=\frac{-4+2\sqrt{19}}{-6}
$